1/2(2x^2-4)+10=11

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Solution for 1/2(2x^2-4)+10=11 equation: 


x in (-oo:+oo)

(1/2)*(2*x^2-4)+10 = 11 // - 11

(1/2)*(2*x^2-4)-11+10 = 0

1/2*(2*x^2-4)-11+10 = 0

1/2*(2*x^2-4)-11+10 = 0

x^2-13+10 = 0

x^2-3 = 0

x^2-3 = 0

1*x^2 = 3 // : 1

x^2 = 3

x^2 = 3 // ^ 1/2

abs(x) = 3^(1/2)

x = 3^(1/2) or x = -3^(1/2)

x in { 3^(1/2), -3^(1/2) }

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